{
 "metadata": {
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.8.6-final"
  },
  "orig_nbformat": 2,
  "kernelspec": {
   "name": "python3",
   "display_name": "Python 3.8.6 64-bit",
   "metadata": {
    "interpreter": {
     "hash": "1ddf53fa84779e14f0db18342168679c9c165a81c5f324dac828befab228d68d"
    }
   }
  }
 },
 "nbformat": 4,
 "nbformat_minor": 2,
 "cells": [
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [],
   "source": [
    "# Get puzzle input from input file\n",
    "\n",
    "puzzle_input = open(\"input\").read().split(\"\\n\")"
   ]
  },
  {
   "source": [
    "# Part 1 #"
   ],
   "cell_type": "markdown",
   "metadata": {}
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "output_type": "stream",
     "name": "stdout",
     "text": [
      "1606483\n"
     ]
    }
   ],
   "source": [
    "wrapping_paper = 0\n",
    "for packet in puzzle_input:\n",
    "    l, w, h = map(lambda val: int(val), packet.split(\"x\"))\n",
    "    # the surface area of the box, which is 2*l*w + 2*w*h + 2*h*l\n",
    "    sides = [l*w*2, w*h*2, l*h*2]\n",
    "    # extra paper for each present: the area of the smallest side.\n",
    "    wrapping_paper += sum(sides) + int(min(sides)/2)\n",
    "print(wrapping_paper)"
   ]
  },
  {
   "source": [
    "# Part 2 #"
   ],
   "cell_type": "markdown",
   "metadata": {}
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "output_type": "stream",
     "name": "stdout",
     "text": [
      "3842356\n"
     ]
    }
   ],
   "source": [
    "ribbon = 0\n",
    "for packet in puzzle_input:\n",
    "    l, w, h = map(lambda val: int(val), packet.split(\"x\"))\n",
    "    # the feet of ribbon required for the perfect bow is equal to the cubic feet of volume of the present\n",
    "    ribbon += l*w*h\n",
    "    # The ribbon required to wrap a present is the shortest distance around its sides, or the smallest perimeter of any one face\n",
    "    x, y = sorted([l, w, h])[0:2]\n",
    "    ribbon += 2*x + 2*y\n",
    "print(ribbon)"
   ]
  }
 ]
}